47x=16x^2

Solution for 47x=16x^2 equation:

47x=16x^2

We move all terms to the left:

47x-(16x^2)=0

determiningTheFunctionDomain
-16x^2+47x=0

a = -16; b = 47; c = 0;
Δ = b2-4ac
Δ = 472-4·(-16)·0
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-47}{2*-16}=\frac{-94}{-32}
=2+15/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+47}{2*-16}=\frac{0}{-32}
=0
$